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/ \[ \frac{2x + 4}{x^2 + 4x + 5} = 0 \]
\[ \frac{2x + 4}{x^2 + 4x + 5} = 0 \]
February 22, 2026
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\[ P = \frac{500}{1 + e^{-0.1(t-5)}} \]
\[ P \to \frac{500}{1 + 0} = 500 \]
\[ R'(x) = \frac{d}{dx}[\ln(x^2 + 4x + 5)] = \frac{2x + 4}{x^2 + 4x + 5} \]
\[ 2x + 4 = 0 \]
\[ x = -2 \]
\[ R''(x) = \frac{(2)(x^2 + 4x + 5) - (2x + 4)(2x + 4)}{(x^2 + 4x + 5)^2} \]
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