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Home / 3(-3) + q = 7 \Rightarrow -9 + q = 7 \Rightarrow q = 16

3(-3) + q = 7 \Rightarrow -9 + q = 7 \Rightarrow q = 16

February 22, 2026

$3(-3) + q = 7 \Rightarrow -9 + q = 7 \Rightarrow q = 16$

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$ 4p + 2q + r = 32 $
$ 9p + 3q + r = 33 $
Substitute into (i):
From (1):
+ 16 + r = 25 \Rightarrow r = 12
So $ A(t) = -3t^2 + 16t + 12 $. The maximum occurs at $ t = -\frac{q}{2p} = -\frac{16}{2(-3

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